More on shrinkage plots

Author

Phillip Alday, Douglas Bates, and Reinhold Kliegl

Published

2025-09-03

Code
using CairoMakie
using DataFrames
using LinearAlgebra
using MixedModels
using MixedModelsMakie
using Random
using ProgressMeter

const progress = false
false

Load the kb07 data set (don’t tell Reinhold that I used these data).

kb07 = MixedModels.dataset(:kb07)
Arrow.Table with 1789 rows, 7 columns, and schema:
 :subj      String
 :item      String
 :spkr      String
 :prec      String
 :load      String
 :rt_trunc  Int16
 :rt_raw    Int16
contrasts = Dict(
  :spkr => HelmertCoding(),
  :prec => HelmertCoding(),
  :load => HelmertCoding(),
)
m1 = let
  form = @formula(
    rt_trunc ~
      1 +
      spkr * prec * load +
      (1 + spkr + prec + load | subj) +
      (1 + spkr + prec + load | item)
  )
  fit(MixedModel, form, kb07; contrasts, progress)
end
Est. SE z p σ_subj σ_item
(Intercept) 2181.6728 77.3040 28.22 <1e-99 301.7798 362.2071
spkr: old 67.7485 18.2919 3.70 0.0002 42.9978 40.6939
prec: maintain -333.9212 47.1520 -7.08 <1e-11 62.0047 246.8895
load: yes 78.7703 19.5373 4.03 <1e-04 65.1516 42.3617
spkr: old & prec: maintain -21.9656 15.8060 -1.39 0.1646
spkr: old & load: yes 18.3843 15.8060 1.16 0.2448
prec: maintain & load: yes 4.5339 15.8060 0.29 0.7742
spkr: old & prec: maintain & load: yes 23.6074 15.8060 1.49 0.1353
Residual 668.4953
VarCorr(m1)
Column Variance Std.Dev Corr.
subj (Intercept) 91071.0419 301.7798
spkr: old 1848.8141 42.9978 +0.78
prec: maintain 3844.5766 62.0047 -0.59 +0.03
load: yes 4244.7317 65.1516 +0.36 +0.83 +0.53
item (Intercept) 131193.9807 362.2071
spkr: old 1655.9905 40.6939 +0.44
prec: maintain 60954.4361 246.8895 -0.69 +0.35
load: yes 1794.5158 42.3617 +0.32 +0.16 -0.14
Residual 446885.9859 668.4953
issingular(m1)
true
print(m1)
Linear mixed model fit by maximum likelihood
 rt_trunc ~ 1 + spkr + prec + load + spkr & prec + spkr & load + prec & load + spkr & prec & load + (1 + spkr + prec + load | subj) + (1 + spkr + prec + load | item)
    logLik   -2 logLik      AIC         AICc        BIC     
 -14318.5613  28637.1227  28695.1227  28696.1119  28854.3156

Variance components:
             Column       Variance  Std.Dev.   Corr.
subj     (Intercept)      91071.0419 301.7798
         spkr: old         1848.8141  42.9978 +0.78
         prec: maintain    3844.5766  62.0047 -0.59 +0.03
         load: yes         4244.7317  65.1516 +0.36 +0.83 +0.53
item     (Intercept)     131193.9807 362.2071
         spkr: old         1655.9905  40.6939 +0.44
         prec: maintain   60954.4361 246.8895 -0.69 +0.35
         load: yes         1794.5158  42.3617 +0.32 +0.16 -0.14
Residual                 446885.9859 668.4953
 Number of obs: 1789; levels of grouping factors: 56, 32

  Fixed-effects parameters:
───────────────────────────────────────────────────────────────────────────────
                                             Coef.  Std. Error      z  Pr(>|z|)
───────────────────────────────────────────────────────────────────────────────
(Intercept)                             2181.67        77.304   28.22    <1e-99
spkr: old                                 67.7485      18.2919   3.70    0.0002
prec: maintain                          -333.921       47.152   -7.08    <1e-11
load: yes                                 78.7703      19.5373   4.03    <1e-04
spkr: old & prec: maintain               -21.9656      15.806   -1.39    0.1646
spkr: old & load: yes                     18.3843      15.806    1.16    0.2448
prec: maintain & load: yes                 4.53388     15.806    0.29    0.7742
spkr: old & prec: maintain & load: yes    23.6074      15.806    1.49    0.1353
───────────────────────────────────────────────────────────────────────────────

1 Expressing the covariance of random effects

Earlier today we mentioned that the parameters being optimized are from a “matrix square root” of the covariance matrix for the random effects. There is one such lower triangular matrix for each grouping factor.

l1 = first(m1.λ)   # Cholesky factor of relative covariance for subj
4×4 LowerTriangular{Float64, Matrix{Float64}}:
  0.451431    ⋅          ⋅          ⋅ 
  0.0502513  0.0401487   ⋅          ⋅ 
 -0.0550302  0.0726991  0.0170162   ⋅ 
  0.0351681  0.0850799  0.0319858  0.0

Notice the zero on the diagonal. A triangular matrix with zeros on the diagonal is singular.

l2 = last(m1.λ)    # this one is also singular
4×4 LowerTriangular{Float64, Matrix{Float64}}:
  0.541824    ⋅           ⋅          ⋅ 
  0.0268639  0.0546256    ⋅          ⋅ 
 -0.253073   0.268004    0.0229392   ⋅ 
  0.0200491  0.00127555  0.0601     0.0

To regenerate the covariance matrix we need to know that the covariance is not the square of l1, it is l1 * l1' (so that the result is symmetric) and multiplied by σ̂²

Σ₁ = varest(m1) .* (l1 * l1')
4×4 Matrix{Float64}:
  91071.0   10137.6     -11101.7     7094.75
  10137.6    1848.81        68.5686  2316.25
 -11101.7      68.5686    3844.58    2142.46
   7094.75   2316.25      2142.46    4244.73
diag(Σ₁)  # compare to the variance column in the VarCorr output
4-element Vector{Float64}:
 91071.04188496091
  1848.8141310725193
  3844.576646699094
  4244.73166099835
sqrt.(diag(Σ₁))
4-element Vector{Float64}:
 301.7797903852425
  42.99783867908385
  62.00465020221543
  65.15160520661291

2 Shrinkage plots

Code
shrinkageplot(m1)
Figure 1: Shrinkage plot of model m1

The upper left panel shows the perfect negative correlation for those two components of the random effects.

shrinkageplot(m1, :item)
X1 = Int.(m1.X')
8×1789 Matrix{Int64}:
  1   1   1   1   1  1   1   1   1   1  …   1   1   1   1   1   1   1  1   1
 -1   1   1  -1  -1  1   1  -1  -1   1      1  -1  -1   1   1  -1  -1  1   1
 -1   1  -1   1  -1  1  -1   1  -1   1     -1   1  -1   1  -1   1  -1  1  -1
  1  -1  -1  -1  -1  1   1   1   1  -1      1   1   1  -1  -1  -1  -1  1   1
  1   1  -1  -1   1  1  -1  -1   1   1     -1  -1   1   1  -1  -1   1  1  -1
 -1  -1  -1   1   1  1   1  -1  -1  -1  …   1  -1  -1  -1  -1   1   1  1   1
 -1  -1   1  -1   1  1  -1   1  -1  -1     -1   1  -1  -1   1  -1   1  1  -1
  1  -1   1   1  -1  1  -1  -1   1  -1     -1  -1   1  -1   1   1  -1  1  -1
X1 * X1'
8×8 Matrix{Int64}:
 1789    -1    -1     3    -3     1     1     3
   -1  1789    -3     1    -1     3     3     1
   -1    -3  1789     1    -1     3     3     1
    3     1     1  1789     3    -1    -1    -3
   -3    -1    -1     3  1789     1     1     3
    1     3     3    -1     1  1789    -3    -1
    1     3     3    -1     1    -3  1789    -1
    3     1     1    -3     3    -1    -1  1789

3 How to interpret a shrinkage plot

  • Extreme shrinkage (shrunk to a line or to a point) is easy to interpret – the term is not providing benefit and can be removed.
  • When the range of the blue dots (shrunk values) is comparable to those of the red dots (unshrunk) it indicates that the term after shrinkage is about as strong as without shrinkage.
  • By itself, this doesn’t mean that the term is important. In some ways you need to get a feeling for the absolute magnitude of the random effects in addition to the relative magnitude.
  • Small magnitude and small relative magnitude indicate you can drop that term

4 Conclusions from these plots

  • Only the intercept for the subj appears to be contributing explanatory power
  • For the item both the intercept and the spkr appear to be contributing
m2 = let
  form = @formula(
    rt_trunc ~
      1 + prec * spkr * load + (1 | subj) + (1 + prec | item)
  )
  fit(MixedModel, form, kb07; contrasts, progress)
end
Est. SE z p σ_item σ_subj
(Intercept) 2181.7582 77.4710 28.16 <1e-99 364.7293 298.1107
prec: maintain -333.8582 47.4631 -7.03 <1e-11 252.6694
spkr: old 67.8114 16.0526 4.22 <1e-04
load: yes 78.6849 16.0525 4.90 <1e-06
prec: maintain & spkr: old -21.8802 16.0525 -1.36 0.1729
prec: maintain & load: yes 4.4710 16.0526 0.28 0.7806
spkr: old & load: yes 18.3214 16.0526 1.14 0.2537
prec: maintain & spkr: old & load: yes 23.5219 16.0525 1.47 0.1428
Residual 678.9319
VarCorr(m2)
Column Variance Std.Dev Corr.
item (Intercept) 133027.438 364.729
prec: maintain 63841.835 252.669 -0.70
subj (Intercept) 88870.014 298.111
Residual 460948.573 678.932
Code
shrinkageplot(m2)
Figure 2: Shrinkage plot of model m2
m3 = let
  form = @formula(
    rt_trunc ~
      1 + prec + spkr + load + (1 | subj) + (1 + prec | item)
  )
  fit(MixedModel, form, kb07; contrasts, progress)
end
Est. SE z p σ_item σ_subj
(Intercept) 2181.8526 77.4680 28.16 <1e-99 364.7121 298.0257
prec: maintain -333.7906 47.4476 -7.03 <1e-11 252.5236
spkr: old 67.8790 16.0785 4.22 <1e-04
load: yes 78.5904 16.0785 4.89 <1e-05
Residual 680.0318
VarCorr(m3)
Column Variance Std.Dev Corr.
item (Intercept) 133014.905 364.712
prec: maintain 63768.184 252.524 -0.70
subj (Intercept) 88819.302 298.026
Residual 462443.261 680.032
rng = Random.seed!(1234321);
m3btstrp = parametricbootstrap(rng, 2000, m3);
DataFrame(shortestcovint(m3btstrp))
9×5 DataFrame
Row type group names lower upper
String String? String? Float64 Float64
1 β missing (Intercept) 2022.91 2334.0
2 β missing prec: maintain -430.239 -239.802
3 β missing spkr: old 34.0592 96.72
4 β missing load: yes 46.5349 109.526
5 σ item (Intercept) 270.065 451.979
6 σ item prec: maintain 181.739 325.127
7 ρ item (Intercept), prec: maintain -0.907255 -0.490094
8 σ subj (Intercept) 233.834 364.504
9 σ residual missing 657.341 702.655
ridgeplot(m3btstrp)
Figure 3: Ridge plot of the fixed-effects coefficients from the bootstrap sample
ridgeplot(m3btstrp; show_intercept=false)
Figure 4: Ridge plot of the fixed-effects coefficients from the bootstrap sample (with the intercept)
m4 = let
  form = @formula(
    rt_trunc ~
      1 + prec + spkr + load + (1 + prec | item) + (1 | subj)
  )
  fit(MixedModel, form, kb07; contrasts, progress)
end
Est. SE z p σ_item σ_subj
(Intercept) 2181.8526 77.4680 28.16 <1e-99 364.7121 298.0257
prec: maintain -333.7906 47.4476 -7.03 <1e-11 252.5236
spkr: old 67.8790 16.0785 4.22 <1e-04
load: yes 78.5904 16.0785 4.89 <1e-05
Residual 680.0318
m4bstrp = parametricbootstrap(rng, 2000, m4);
ridgeplot(m4bstrp; show_intercept=false)
DataFrame(shortestcovint(m4bstrp))
9×5 DataFrame
Row type group names lower upper
String String? String? Float64 Float64
1 β missing (Intercept) 2034.15 2335.45
2 β missing prec: maintain -427.769 -248.337
3 β missing spkr: old 35.6938 97.8081
4 β missing load: yes 45.3095 107.368
5 σ item (Intercept) 260.498 451.649
6 σ item prec: maintain 179.495 315.414
7 ρ item (Intercept), prec: maintain -0.901831 -0.471356
8 σ subj (Intercept) 236.684 360.363
9 σ residual missing 657.178 702.739
VarCorr(m4)
Column Variance Std.Dev Corr.
item (Intercept) 133014.905 364.712
prec: maintain 63768.184 252.524 -0.70
subj (Intercept) 88819.302 298.026
Residual 462443.261 680.032
Code
let mods = [m1, m2, m4]
  DataFrame(;
    geomdof=(sum  leverage).(mods),
    npar=dof.(mods),
    deviance=deviance.(mods),
    AIC=aic.(mods),
    BIC=bic.(mods),
    AICc=aicc.(mods),
  )
end
3×6 DataFrame
Row geomdof npar deviance AIC BIC AICc
Float64 Int64 Float64 Float64 Float64 Float64
1 131.593 29 28637.1 28695.1 28854.3 28696.1
2 107.543 13 28658.5 28684.5 28755.8 28684.7
3 103.478 9 28663.9 28681.9 28731.3 28682.0
scatter(fitted(m4), residuals(m4))
Figure 5: Residuals versus fitted values for model m4

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